Java Program to Display Armstrong Numbers

This post shows how you can generate and display Armstrong numbers in Java with in the given range. A number is an Armstrong number if it is equal to the sum of its digit raised to the power of count of digits in the number.

As example– 371 = 33 + 73 + 13 = 27 + 343 +1 = 371

Number of digits is 3 here so every digit is raised to the power of 3 and added. Since the calculated number is equal to the original number so 371 is an Armstrong number.

1634 = 14 + 6 4 + 34 + 44 = 1 + 1296 + 81 + 256 = 1634

Display Armstrong numbers within the given range – Java Program

```import java.util.Scanner;

public class ArmstrongNumber {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter start number for displaying Armstrong numbers  - ");
int start = sc.nextInt();

System.out.println("Enter end number for displaying Armstrong numbers  - ");
int end = sc.nextInt();
System.out.print("Armstrong numbers with in " + start + " and " + end + "- ");
for(int i = start; i <= end; i++){
if(checkIfArmstrong(i)){
System.out.print(i + " ");
}
}
sc.close();
}
private static boolean checkIfArmstrong(int number){
// Converting to string and calculating length
int numLength = (number+"").length();
int temp = number;
int sum = 0;
while(temp > 0 ){
int remainder = temp % 10;
sum = sum + (int)Math.pow(remainder, numLength);
temp = temp/10;
}
if(number == sum){
return true;
}else{
return false;
}
}
}
```

Output

```Enter start number for displaying Armstrong numbers  -
10
Enter end number for displaying Armstrong numbers  -
10000

Armstrong numbers with in 10 and 10000- 153 370 371 407 1634 8208 9474
```

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